NAME
       lreplace - Replace elements in a list with new elements

SYNOPSIS
       lreplace list first last ?element element ...?


DESCRIPTION
       lreplace  returns  a  new  list formed by replacing one or
       more elements of list with the element  arguments.   first
       and  last specify the first and last index of the range of
       elements to replace.  0 refers to the first element of the
       list,  and  end (or any abbreviation of it) may be used to
       refer to the last element of the list.  If list is  empty,
       then first and last are ignored.

       If  first  is less than zero, it is considered to refer to
       the first element of the list.  For non-empty  lists,  the
       element indicated by first must exist.

       If last is less than zero but greater than first, then any
       specified elements will be prepended to the list.  If last
       is  less  than first then no elements are deleted; the new
       elements are simply inserted before first.

       The element arguments specify zero or more  new  arguments
       to  be  added  to  the  list  in  place of those that were
       deleted.  Each element argument  will  become  a  separate
       element  of  the list.  If no element arguments are speci-
       fied, then the elements between first and last are  simply
       deleted.   If  list  is  empty,  any element arguments are
       added to the end of the list.


SEE ALSO
       list(n), lappend(n),  lindex(n),  linsert(n),  llength(n),
       lsearch(n), lset(n), lrange(n), lsort(n)


KEYWORDS
